Number (3): Everything in this space must add up to 3. The answer is 1-1, placed horizontally; 1-4, placed vertically.
Now that we can build the tree, let's use it to search. Finding a specific point means starting at the root and asking: which child quadrant contains this coordinate? Then you recurse into that child and ask again. Each level of the tree cuts the search space by roughly three-quarters.
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// 数组完全有序，直接返回0
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while (stack.length && temperatures[stack.at(-1)] <= cur) {
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